1866 Rhode Island gubernatorial election

1866 Rhode Island gubernatorial election

← 1865 4 April 1866 1867 →
 
Nominee Ambrose Burnside Lyman Pierce
Party Republican Democratic
Popular vote 8,197 2,816
Percentage 73.36% 25.20%

County results
Burnside:      60–70%      70–80%      80–90%

Governor before election

James Y. Smith
Republican

Elected Governor

Ambrose Burnside
Republican

The 1866 Rhode Island gubernatorial election was held on 4 April 1866 in order to elect the governor of Rhode Island. Republican nominee and former Union Army Major General Ambrose Burnside defeated Democratic nominee Lyman Pierce.[1]

  1. ^ "Ambrose Burnside". National Governors Association. Retrieved 7 April 2024.

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