1940 United States presidential election in Utah

1940 United States presidential election in Utah

← 1936 November 5, 1940 1944 →
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 4 0
Popular vote 154,277 93,151
Percentage 62.25% 37.59%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Utah took place on November 5, 1940 as part of the 1940 United States presidential election. All contemporary forty-eight states took part, and state voters selected four voters to the Electoral College, who voted for president and vice president.

Utah, like every other state west of the Continental Divide, voted for Franklin D. Roosevelt over Wendell Willkie by a substantial margin. This was the first time any Democrat won the state more than twice. Roosevelt landslided Utah with 62.25 percent of the vote. The percentage, however, wasn’t as large as his victory in the state four years earlier. As of the 2020 presidential election, this is the last election in which Piute County voted for a Democratic presidential candidate.[1]

  1. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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