Back كأس ديفيز 1948 Arabic Davis Cup 1948 German Copa Davis 1948 Spanish Coupe Davis 1948 French גביע דייוויס 1948 HE Coppa Davis 1948 Italian Davis Cup 1948 Dutch Copa Davis de 1948 Portuguese Davisov pokal 1948 Slovenian
| Details | |
|---|---|
| Duration | 22 April – 6 September 1948 |
| Edition | 37th |
| Teams | 29 |
| Champion | |
| Winning nation |  United States |
← 1947 1949 → | |
The 1948 Davis Cup was the 37th edition of the most important tournament between national teams in men's tennis. 25 teams entered the Europe Zone, and four teams entered the America Zone. Pakistan and Turkey made their first appearances in the competition.
Australia defeated Mexico in the America Zone final, and Czechoslovakia defeated Sweden in the Europe Zone final. Australia defeated Czechoslovakia in the Inter-Zonal play-off, but fell to defending champions the United States in the Challenge Round. The championship was played at the West Side Tennis Club in Forest Hills, New York, United States on 4–6 September.[1][2][3]
- ^ Bud Collins (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. pp. 495–496, 499. ISBN 978-0942257700.
- ^ Max Robertson (1974). The Encyclopedia of Tennis. London: Allen & Unwin. p. 384. ISBN 0047960426.
- ^ Cite error: The named reference
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