![]() | |
Tournament details | |
---|---|
Host country | United States |
Dates | 4 – 17 October |
Teams | 8 (from 1 confederation) |
Venue(s) | 3 (in 3 host cities) |
Final positions | |
Champions | ![]() |
Runners-up | ![]() |
Third place | ![]() |
Fourth place | ![]() |
Tournament statistics | |
Matches played | 16 |
Goals scored | 83 (5.19 per match) |
Top scorer(s) | ![]() |
Best player(s) | ![]() |
Best young player | ![]() |
Best goalkeeper | ![]() |
Fair play award | ![]() |
The 2018 CONCACAF Women's Championship was the 10th edition of the CONCACAF Women's Championship (also known as the CONCACAF Women's Gold Cup or the CONCACAF Women's World Cup Qualifying Tournament), the quadrennial international football championship organized by CONCACAF for the women's national teams of the North, Central American and Caribbean region. Eight teams played in the tournament, which took place from 4 to 17 October 2018 in the United States.[1][2]
The tournament served as the CONCACAF qualifiers to the 2019 FIFA Women's World Cup in France. The top three teams qualified for the World Cup, while the fourth-placed team advanced to a play-off against the third-placed team from the South American confederation, CONMEBOL.[3] It also determined the CONCACAF teams playing at the 2019 Pan American Games women's football tournament in Lima, Peru.[4]
The United States were the defending champions of the competition. They successfully defended their title as hosts, winning the final 2–0 against Canada for their 8th CONCACAF Women's Championship title.[5]
This was the last CONCACAF tournament branded as the "Women's Championship". In August 2019, CONCACAF announced a rebranding of the competition as the CONCACAF W Championship.[6]