Hobart Township | |
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Coordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W | |
Country | United States |
State | Indiana |
County | Lake |
Government | |
• Type | Indiana township |
Area | |
• Total | 25.98 sq mi (67.3 km2) |
• Land | 25.47 sq mi (66.0 km2) |
• Water | 0.51 sq mi (1.3 km2) |
Elevation | 627 ft (191 m) |
Population | |
• Total | 40,652 |
• Density | 1,547.4/sq mi (597.5/km2) |
FIPS code | 18-34132[3] |
GNIS feature ID | 453414 |
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[4]
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 2,197 | — | |
1900 | 2,718 | 23.7% | |
1910 | 3,729 | 37.2% | |
1920 | 5,621 | 50.7% | |
1930 | 9,135 | 62.5% | |
1940 | 12,472 | 36.5% | |
1950 | 21,871 | 75.4% | |
1960 | 39,223 | 79.3% | |
1970 | 40,825 | 4.1% | |
1980 | 42,548 | 4.2% | |
1990 | 38,942 | −8.5% | |
2000 | 39,636 | 1.8% | |
2010 | 39,417 | −0.6% | |
2020 | 40,652 | 3.1% | |
Source: US Decennial Census[5] |