Jefferson County | |
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![]() Location within the U.S. state of Ohio | |
![]() Ohio's location within the U.S. | |
Coordinates: 40°23′N 80°46′W / 40.38°N 80.76°W | |
Country | ![]() |
State | ![]() |
Founded | July 29, 1797[1] |
Named for | Thomas Jefferson |
Seat | Steubenville |
Largest city | Steubenville |
Area | |
• Total | 411 sq mi (1,060 km2) |
• Land | 408 sq mi (1,060 km2) |
• Water | 2.6 sq mi (7 km2) 0.6% |
Population (2020) | |
• Total | 65,249 ![]() |
• Density | 160/sq mi (60/km2) |
Time zone | UTC−5 (Eastern) |
• Summer (DST) | UTC−4 (EDT) |
Congressional district | 6th |
Website | www |
Jefferson County is a county located in the U.S. state of Ohio. As of the 2020 census, the population was 65,249.[2] Its county seat is Steubenville.[3] The county is named for Thomas Jefferson, who was vice president at the time of its creation.[4]
Jefferson County is part of the Weirton–Steubenville, WV–OH Metropolitan Statistical Area, which is also included in the Pittsburgh–New Castle–Weirton, PA–WV–OH Combined Statistical Area.[5]
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: CS1 maint: archived copy as title (link)