Back Jefferson Township (Ashtabula County, Ohio) German Municipio de Jefferson (condado de Ashtabula) Spanish Jefferson udalerria, Ashtabula konderria (Ohio) Basque بخش جفرسون، شهرستان اشتابولا، اوهایو Persian Município de Jefferson (condado de Ashtabula, Ohio) Portuguese Xã Jefferson, Quận Ashtabula, Ohio Vietnamese
Jefferson Township, Ashtabula County, Ohio | |
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 Location of Jefferson Township in Ashtabula County | |
| Coordinates: 41°44′41″N 80°45′46″W / 41.74472°N 80.76278°W | |
| Country | United States |
| State | Ohio |
| County | Ashtabula |
| Area | |
| • Total | 25.9 sq mi (67.0 km2) |
| • Land | 25.8 sq mi (66.7 km2) |
| • Water | 0.1 sq mi (0.3 km2) |
| Elevation | 906 ft (276 m) |
| Population (2020) | |
| • Total | 5,317 |
| • Density | 204/sq mi (78.8/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 44047 |
| Area code | 440 |
| FIPS code | 39-38514[2] |
| GNIS feature ID | 1085729[1] |
Jefferson Township is one of the twenty-seven townships of Ashtabula County, Ohio, United States. The population was 5,317 at the 2020 census.[3]
- ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "Jefferson township, Ashtabula County, Ohio - Census Bureau Profile". United States Census Bureau. Retrieved May 17, 2023.