Jefferson Township, Ashtabula County, Ohio | |
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![]() Location of Jefferson Township in Ashtabula County | |
Coordinates: 41°44′41″N 80°45′46″W / 41.74472°N 80.76278°W | |
Country | United States |
State | Ohio |
County | Ashtabula |
Area | |
• Total | 25.9 sq mi (67.0 km2) |
• Land | 25.8 sq mi (66.7 km2) |
• Water | 0.1 sq mi (0.3 km2) |
Elevation | 906 ft (276 m) |
Population (2020) | |
• Total | 5,317 |
• Density | 204/sq mi (78.8/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 44047 |
Area code | 440 |
FIPS code | 39-38514[2] |
GNIS feature ID | 1085729[1] |
Jefferson Township is one of the twenty-seven townships of Ashtabula County, Ohio, United States. The population was 5,317 at the 2020 census.[3]