Back Jefferson Township (Brown County, Ohio) German Municipio de Jefferson (condado de Brown) Spanish Jefferson udalerria, Brown konderria (Ohio) Basque بخش جفرسون، شهرستان براون، اوهایو Persian Município de Jefferson (condado de Brown, Ohio) Portuguese Xã Jefferson, Quận Brown, Ohio Vietnamese
Jefferson Township, Brown County, Ohio | |
|---|---|
 Farmstead southeast of Russellville | |
 Location of Jefferson Township in Brown County | |
| Coordinates: 38°51′21″N 83°47′28″W / 38.85583°N 83.79111°W | |
| Country | United States |
| State | Ohio |
| County | Brown |
| Area | |
| • Total | 23.47 sq mi (60.78 km2) |
| • Land | 23.45 sq mi (60.74 km2) |
| • Water | 0.01 sq mi (0.03 km2) |
| Elevation | 925 ft (282 m) |
| Population (2020) | |
| • Total | 1,407 |
| • Density | 60/sq mi (23/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| FIPS code | 39-38528[2] |
| GNIS feature ID | 1085799[1] |
Jefferson Township is one of the sixteen townships of Brown County, Ohio, United States. The 2020 census found 1,407 people in the township.[3]
- ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "Jefferson township, Brown County, Ohio - Census Bureau Profile". United States Census Bureau. Retrieved May 26, 2023.