1824 United States presidential election

John Quincy Adams

Andrew Jackson

William H. Crawford

Henry Clay

In the United States presidential election of 1824, John Quincy Adams was elected the sixth President of the United States.^[1] There were five candidates for president: John Quincy Adams, John C. Calhoun, William H. Crawford , Henry Clay and Andrew Jackson.^[2] Jackson was by far the most popular candidate.^[2] The winner of the Electoral College was Jackson who had 99 votes.^[3] Adams was second with 84 votes.^[3] Crawford won 41 votes while Clay won only 37.^[3] For the first time since 1801 the United States House of Representatives would decide the election.^[4] Under the Twelfth Amendment to the United States, with no Electoral College winner, the President would be voted on from among the top three candidates.^[2] Meeting in February 1825, Adams won by a single vote.^[2] Adams was the son of the second President of the United States, John Adams.

1. ↑ "The 1824 Election and the "Corrupt Bargain"". USHistory.org. The Independence Hall Association. Archived from the original on November 25, 2016. Retrieved December 9, 2016.
2. ↑ ^{2.0 2.1 2.2 2.3} "John Quincy Adams: Campaigns and Elections | Miller Center". millercenter.org. 2016-10-04. Archived from the original on 2022-03-23. Retrieved 2022-05-01.
3. ↑ ^{3.0 3.1 3.2} "1825 Presidential election decided in the House". This Day in History. A&E Television Networks, LLC. Archived from the original on December 7, 2016. Retrieved December 9, 2016.
4. ↑ Edward G. Lengel. "Adams v. Jackson: The Election of 1824". History Now. The Gilder Lehrman Institute of American History. Archived from the original on December 8, 2016. Retrieved December 9, 2016.