Jefferson, Ohio

Jefferson, Ohio
Village
Ashtabula County Courthouse
Location of Jefferson, Ohio
Location of Jefferson in Ashtabula County
Coordinates: 41°44′19″N 80°45′25″W / 41.73861°N 80.75694°W / 41.73861; -80.75694
Country	United States
State	Ohio
County	Ashtabula
Area [1]
• Total	2.54 sq mi (6.57 km2)
• Land	2.54 sq mi (6.57 km2)
• Water	0.00 sq mi (0.00 km2)
Elevation [2]	961 ft (293 m)
Population  (2020)[3]
• Total	3,226
• Density	1,271.58/sq mi (491.04/km2)
Time zone	UTC-5 (Eastern (EST))
• Summer (DST)	UTC-4 (EDT)
ZIP code	44047
Area code	440
FIPS code	39-38500[4]
GNIS feature ID	1042061[2]
Website	https://jeffersonohio.gov/

Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.^[3] It is the county seat of Ashtabula County.^[5]

1. ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
2. ↑ ^{2.0 2.1} U.S. Geological Survey Geographic Names Information System: Jefferson, Ohio
3. ↑ ^{3.0 3.1} "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson village, Ohio". United States Census Bureau. Retrieved March 16, 2024.
4. ↑ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
5. ↑ National Association of Counties. "NACo County Explorer". Retrieved March 15, 2024.